oooo
发表于 2008-5-15 09:41:04
x下载了!第一次见二阶的盲拧:handshake :victory: :hug:
乌木
发表于 2008-5-27 10:21:52
<P>文中这两个图最好互换一下,因为一般人习惯把公式前的图看作公式要解决的初态。</P>
<P></P>
<P> </P>
QQ406263
发表于 2008-5-27 10:27:16
:lol :lol 二阶~绝对简单~~
乌木
发表于 2008-5-27 15:21:20
<SPAN lang=EN-US style="FONT-SIZE: 12pt; COLOR: blue; FONT-FAMILY: 'Times New Roman'; mso-fareast-font-family: 宋体; mso-font-kerning: 1.0pt; mso-ansi-language: EN-US; mso-fareast-language: ZH-CN; mso-bidi-language: AR-SA"><SPAN lang=EN-US style="FONT-SIZE: 12pt; COLOR: blue; FONT-FAMILY: 'Times New Roman'; mso-fareast-font-family: 宋体; mso-font-kerning: 1.0pt; mso-ansi-language: EN-US; mso-fareast-language: ZH-CN; mso-bidi-language: AR-SA">
<P class=MsoNormal style="MARGIN: 0cm 0cm 0pt"><SPAN style="FONT-SIZE: 12pt; FONT-FAMILY: 宋体; mso-font-kerning: 0pt; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'"><FONT color=#000000>教程中讲位置调整法的时候,前面举例为(46574),后面的具体操作变为47865。最好前后一致。</FONT></SPAN></P></SPAN></SPAN>
kexin_xiao
发表于 2008-5-27 15:58:29
我也和农民探讨过后面调整位置部分的问题,建议农民修改的再通俗一点。
乌木
发表于 2008-5-27 16:20:48
<P>有人要看看java 演示的例子。下面用三阶的角块代替二阶。第一图为初态,已经整体翻滚得3号角(红-绿-黄)处于复原态。色向编码为1101 1221 ,位置编码及将做的循环解码为 (282)(47654)。</P>
<P> </P>
<applet code="RubikPlayer.class" codebase=3 width="250" height="250">
<param name="ColorTable" value="0xf8f8f8,0x00732f,0xff4400,0xffd200,0x003373,0x8c000f,0x858585">
<param name="scrptLanguage" value="SupersetENG">
<param name="beta" value="29">
<param name="stickersFront" value="4,6,2,6,6,6,5,6,3">
<param name="stickersRight" value="3,6,1,6,6,6,5,6,2">
<param name="stickersDown" value="1,6,4,6,6,6,0,6,4">
<param name="stickersBack" value="3,6,2,6,6,6,3,6,2">
<param name="stickersLeft" value="1,6,5,6,6,6,4,6,0">
<param name="stickersUp" value="0,6,5,6,6,6,0,6,1">
</applet>
<applet code="RubikPlayer.class" codebase=3 width="300" height="400">
<param name="ColorTable" value="0xf8f8f8,0x00732f,0xff4400,0xffd200,0x003373,0x8c000f,0x858585">
<param name="scrptLanguage" value="SupersetENG">
<param name="scrpt" value="(R U R' U R U2 R' L' U' L U' L' U2 L) \n R2 B2 (R U R' U R U2 R' L' U' L U' L' U2 L)B2 R2 \n D2 B2 (R U R' U R U2 R' L' U' L U' L' U2 L)B2 D2 \n D' B2 (L' U2 L U L' U L R U2 R' U' R U' R' )B2 D \n B2 (L' U2 L U L' U L R U2 R' U' R U' R' )B2 \n D B2 (R U R' U R U2 R' L' U' L U' L' U2 L)B2 D' ">
<param name="beta" value="29">
<param name="stickersFront" value="4,6,2,6,6,6,5,6,3">
<param name="stickersRight" value="3,6,1,6,6,6,5,6,2">
<param name="stickersDown" value="1,6,4,6,6,6,0,6,4">
<param name="stickersBack" value="3,6,2,6,6,6,3,6,2">
<param name="stickersLeft" value="1,6,5,6,6,6,4,6,0">
<param name="stickersUp" value="0,6,5,6,6,6,0,6,1">
</applet>
<P> </P>
未完
乌木
发表于 2008-5-27 16:39:33
17楼的复原态取上红前白右绿……
乌木
发表于 2008-5-27 16:51:28
<P>继续调位置,1号角无循环,3号角初始即处于复原态,解码:(282)(47654)。</P>
<P> </P>
<applet code="RubikPlayer.class" codebase=3 width="300" height="420">
<param name="ColorTable" value="0xf8f8f8,0x00732f,0xff4400,0xffd200,0x003373,0x8c000f,0x858585">
<param name="scrptLanguage" value="SupersetENG">
<param name="scrpt" value="( R U' L' U R' U2 L U' L' U2 L) \n D B2 ( R U' L' U R' U2 L U' L' U2 L)B2 D' \n ( R U' L' U R' U2 L U' L' U2 L)\n R2 B2( R U' L' U R' U2 L U' L' U2 L) B2 R2 \n B2 ( R U' L' U R' U2 L U' L' U2 L)B2 \n D' B2( R U' L' U R' U2 L U' L' U2 L) B2 D \n D2 B2 ( R U' L' U R' U2 L U' L' U2 L)B2 D2 \n R2 B2( R U' L' U R' U2 L U' L' U2 L) B2 R2 ">
<param name="beta" value="29">
<param name="stickersFront" value="0,6,3,6,6,6,0,6,4">
<param name="stickersRight" value="1,6,1,6,6,6,3,6,3">
<param name="stickersDown" value="5,6,5,6,6,6,2,6,2">
<param name="stickersBack" value="3,6,1,6,6,6,4,6,4">
<param name="stickersLeft" value="0,6,4,6,6,6,0,6,1">
<param name="stickersUp" value="2,6,5,6,6,6,5,6,2">
</applet>
kexin_xiao
发表于 2008-5-27 17:40:53
乌木老师的JAVA很直观,顶起来!
kexin_xiao
发表于 2008-5-27 17:41:20
乌木老师的JAVA很直观,顶起来!