cube_master 发表于 2005-3-18 00:07:56

3 月 11 日题目

<P>3 月 11 日求最少移动步数题目</P>
<P>摘自：<a href="http://www.necrophagous.co.uk/cubestation/fmcresults/fmc.php" target="_blank" >http://www.necrophagous.co.uk/cubestation/fmcresults/fmc.php</A></P>
<P>打乱：B' D2 L' (F2 U R' F' D)*4 U2 R' B(U D' L2 F' R)*4 D' L2 F'</P>
<applet code="RubikPlayer.class" codebase=3 width="300" height="300">
  <param name="scrptLanguage" value="HarrisENG">
  <param name="scrpt" value="B' D2 L' (F2 U R' F' D)*4 U2 R' B(U D' L2 F' R)*4 D' L2 F'">
  <param name="scrptProgress" value="-1">
</applet>

cube_master 发表于 2005-3-22 00:40:40

<P>这次没有时间作最少步还原的探索了，就按我自己的还原系统进行复原吧，希望能给想了解我的还原方法的朋友有帮助。</P>
<P>2 X 2 X 3</P>
<applet code="RubikPlayer.class" codebase=3 width="300" height="300">
  <param name="scrptLanguage" value="HarrisENG">
  <param name="scrpt" value="U'RF'LDF'DR2D'B'R'B2F'LB'">
  <param name="initScrpt" value="B' D2 L' (F2 U R' F' D)*4 U2 R' B(U D' L2 F' R)*4 D' L2 F'">
</applet>

cube_master 发表于 2005-3-22 00:46:17

<P>二层</P>
<applet code="RubikPlayer.class" codebase=3 width="300" height="300">
  <param name="scrptLanguage" value="HarrisENG">
  <param name="scrpt" value="F'RU'R'U'L'U2LFUF'U'FR'F'R">
  <param name="initScrpt" value="B' D2 L' (F2 U R' F' D)*4 U2 R' B(U D' L2 F' R)*4 D' L2 F'U'RF'LDF'DR2D'B'R'B2F'LB'">
</applet>

cube_master 发表于 2005-3-22 01:01:35

<P>完成</P>
<P>由于本例的特殊性，这里使用了一个小技巧，先转 <FONT color=#0000ff>ML</FONT> 便可节省了<FONT color=#ff0000>OLL</FONT> 一步，从而直接用 <FONT color=#ff0000>PLL</FONT> ，完成后再转 <FONT color=#0000ff>ML' </FONT>，最后转 <FONT color=#0000ff>U</FONT> ，整个魔方便还原了<img src="http://bbs.mf8-china.com/Skins/default/topicface/face1.gif"> </P>
<applet code="RubikPlayer.class" codebase=3 width="300" height="360">
  <param name="scrptLanguage" value="SupersetENG">
  <param name="scrpt" value="ML\nCR\nR UR'F2LD'L'U'L2DL2UF2\nML'\nU">
  <param name="initScrpt" value="B'D2L'(F2UR'F'D)4U2R'B(UD'L2F'R)4D'L2F'U'RF'LDF'DR2D'B'R'B2F'LB'F'RU'R'U'L'U2LFUF'U'FR'F'R">
</applet>
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