看一下这个公式,倒过来用就成了
<applet code="RubikPlayer.class" codebase=3 width="300" height="300">
<param name="scrptLanguage" value="HarrisENG">
<param name="scrpt" value="R U R' U R U2 R' L' U' L U' L' U2 L ">
</applet>作者: Alexan 时间: 2006-4-18 12:10:16
楼上的图如下,其中U'是把第2个角转到右边来翻,最后的U把它转回去:
<applet code="RubikPlayer.class" codebase=3 width="200" height="200">
<param name="scrptLanguage" value="SupersetENG">
<param name="scrpt" value="R F' R' F R F' R' F U' F' R F R' F' R F R' U ">
<param name="stickersFront" value="5,0,5,0,0,0,0,0,0">
<param name="stickersRight" value="0,1,1,1,1,1,1,1,1">
<param name="stickersLeft" value="4,4,0,4,4,4,4,4,4">
<param name="stickersUp" value="5,5,5,5,5,5,4,5,1">
</applet>作者: Alexan 时间: 2006-4-18 14:29:47
<>回3楼,那java图底下的一行符号即公式。他要你倒过来用,就是:L'U2 L U L'U L R U2 R'U'R U'R'</P>
<>但先要把待翻的两个角置于左边!</P>作者: 乌木 时间: 2006-4-18 17:34:25
如果还是要让待翻的两个角处于前面,则要变换公式:F'U2FUF'UFBU2B'U'BU'B' ;如果两个角待转的方向是相反的一对,则做:
BUB'UBU2B'F'U'FU'F'U2F 。见下两图:
<applet code="RubikPlayer.class" codebase=3 width="200" height="200">
<param name="scrptLanguage" value="SupersetENG">
<param name="scrpt" value="F' U2 F U F' U F B U2 B' U' B U' B' ">
<param name="stickersFront" value="5,0,5,0,0,0,0,0,0">
<param name="stickersRight" value="0,1,1,1,1,1,1,1,1">
<param name="stickersLeft" value="4,4,0,4,4,4,4,4,4">
<param name="stickersUp" value="5,5,5,5,5,5,4,5,1">
</applet><applet code="RubikPlayer.class" codebase=3 width="200" height="200">
<param name="scrptLanguage" value="SupersetENG">
<param name="scrpt" value="BUB'UBU2B'F'U'FU'F'U2F">
<param name="stickersFront" value="4,0,1,0,0,0,0,0,0">
<param name="stickersRight" value="5,1,1,1,1,1,1,1,1">
<param name="stickersLeft" value="4,4,5,4,4,4,4,4,4">
<param name="stickersUp" value="5,5,5,5,5,5,0,5,0">
</applet>作者: 乌木 时间: 2006-4-18 20:26:54
索性把翻四个角的公式画于下面(从论坛里抄下的,一时找不到出处,对不起了。
<applet code="RubikPlayer.class" codebase=3 width="200" height="200">
<param name="scrptLanguage" value="SupersetENG">
<param name="scrpt" value="F R U R' U' F' TF R U R' U' TF' F R U R' U' F' TF R U R' U' TF' ">
<param name="stickersFront" value="5,0,1,0,0,0,0,0,0">
<param name="stickersRight" value="5,1,5,1,1,1,1,1,1">
<param name="stickersBack" value="1,3,5,3,3,3,3,3,3">
<param name="stickersLeft" value="3,4,0,4,4,4,4,4,4">
<param name="stickersUp" value="4,5,3,5,5,5,4,5,0">
</applet>
如果两个对角要顺翻,另两个对角要逆翻,类似的单一个公式该如何,我就不会了。对此,我是用我上面说的“慢法”,逐个逐个去翻正,口中念叨着口诀“出出进进,出出进进。……”慢,但是万无一失。