按以下步骤打乱,然后用自己的方法还原,看看要多少步。我还不会发带java图的帖子。图就补发了。 B L U R (F2 D' U2 R')*5 F L U (D2 F' R L)*3 F L U B
你可以试试由老猫提供的 Java 贴助手,很轻易的帮你发带 Java 的贴子
本期的题目
[此贴子已经被作者于2004-10-24 10:20:39编辑过]
to cube_master 老大
你上面的图与原题不同。原题的是(D2 F' R L)*3,你的变成了(D2 F' R L)*4了
to cube_master 老大
你上面的图与原题不同。原题的是(D2 F' R L)*3,你的变成了(D2 F' R L)*4了
谢谢,改了!
[em04]十字 4步
L D U2 L2前两层1 :6步
U L U3 R3 U3 R
前两层2 :6步
U L3 U2 F U F3
[此贴子已经被作者于2004-10-25 21:12:36编辑过]
L3 U L U3 F U R U3 R3
顶一色:7步R B2 L3 B3 L B3 R3 U
最后一着:10步L2 F U F3 L2 B D3 B D B2
十字 4步
前两层 26步
顶一色:7步
最后一着:10步
晕。。。。。。47步
哈哈,如果在真正的比赛中能发挥出47步的成绩已经是很不错了。
因此我们需要多做这样的练习,会提高比赛时的反应能力。
我的方法,46步 D3 R3 U3 R3 F U F3 D3 U3 R D2 U3 L3 D L3 U L F3 L F2 L3 F3 L F2 L3 D R2 U3 R2 D3 R U R3 D3 F2 D2 F D3 F3 D3 F2 U L D L3 U3
D3 R3 U3 R3 F U F3D3 U3 R D2 U3 L3 D
L3 U L
F3 L F2 L3 F3 L F2 L3
D R2 U3 R2 D3 R U R3
D3 F2 D2 F D3 F3 D3 F2 U L D L3 U3
合并最后两步 D3 R3 U3 R3 F U F3 D3 U3 R D2 U3 L3 D L3 U L F3 L F2 L3 F3 L F2 L3 R3 F3 D3 F L3 D R D3 F3 L F D
[此贴子已经被作者于2004-10-26 0:55:44编辑过]
[此贴子已经被作者于2004-10-26 0:21:00编辑过]
在cube_master的基础上加以改进,41步 U2 F B2 D3 R D2 B2 F3 D B3 L2 B3 L F2 L3 U R3 F R U F R3 F R F2 B L2 F3 L3 F L3 B3 B2 U L3 R B2 L R3 U B2 U2
合并最后两步,36步 U2 F B2 D3 R D2 B2 F3 D B3 L2 B3 L F2 L3 U R3 F R U F R3 F R F2 B L3 D3 L3 D2 R F2 R3 D3 L2 B3
唉,还是老外的水平高几个级数!
看看这期的最佳答案:http://www.necrophagous.co.uk/cubestation/fmcresults/fmcresults221004.php
28步:[1] U' R2 U B U2 L D L R2 B2 [2] U2 R' B' R' B [3] R U2 R' U R2 U' R2 U' R' U R' U' R - HTM = 28 moves QTM = [36 moves] STM = {28 moves}
用老猫的贴助手编了一下贴出来看看:
1, 2*2*3(10步) U' R2 U B U2 L D L R2 B2 2。U2 R' B' R' B
3。R U2 R' U R2 U' R2 U' R' U R' U' R
22/10/04 FMC #60 | Scrambling algorithm: B L U R (F2 D' U2 R')*5 F L U (D2 F' R L)*3 F L U B | |||
Pos. | Name | Country | Solution | Quote |
=1 [=1] {=1} | Charles Tsai 603 | USA | [1] U' R2 U B U2 L D L R2 B2 [2] U2 R' B' R' B [3] R U2 R' U R2 U' R2 U' R' U R' U' R - HTM = 28 moves QTM = [36 moves] STM = {28 moves} | Saved by a shorter-than-usual step 3. |
=1 [=1] {=1} | Mirek Goljan 709 | USA/Czech | B' R' D R' D L F2 U' F2 R2 F R F2 U F U2 R U F2 D B' R B' R' U2 B' U R2 - HTM = 28 moves QTM = [36 moves] STM = {28 moves} | After not an unusual start B' R' D R' D L F2 U'. D B2 U' 2X2X3 is done. Continue U B R B' R' U2 B' U R2 and 2 edges yet to be flipped and 3 corners twisted. This can be done in 9 turns like R2 F R F2 U F U2 R U after the first U' turn at the dot sign if we help with F2 |
3 [=3] {3} | Sebastian Dumitrescu 601 | Romania | D' L' F' {U2 D2} F2 B L2 F2 R B F U' L' U' {L R'} F R L F' L' U2 F' U' F2 U' F2 U2 F U' - HTM = 31 moves QTM = [40 moves] STM = {29 moves} | This position was remarcable in that you couldn't build a corner-edge pair in one move, you needed two moves, so I tried to find another start than forming pairs. I exploited the two corners WOB and WOG, making a nice WO 2x2x3 in ten moves D' L' F' U2 D2 F2 B L2.R B , with the F2 move inserted at the dot orienting two edges. Then F U'. L F' L' is step 2. The step 3 moves U2 F' U' F2 U' F2 U2 F U' are a Rune which solves the corners and two edges, the last 5 edges being permuted L' U' L R' F R in the middle of step 2, at the dot as usually. I like this solution, I was very satisfied when I solved those 5 edges, even if moves didn't cancel out. Next week I'll do sub-30! |
4 [=3] {4} | Zbigniew Zborowski 582 | Poland | [1] U' B' U' L B' R U R' U' D2 F' U' F U' R' U' R [/1] D2 [2] F U F' L' B' U' B U' [= U L [/2] [3] L' U2] L U2 L F' L B L B' L F [/3] D - HTM = 37 moves QTM = [40 moves] STM = {37 moves} | just do not look at my (bad) solution zz |
5 [5] {5} | Thomas Bischof 394 provisional | USA | L D' R2 D2 L' U' R U R' U2 L U' L U2 L' U' L U L' R2 U2 R U R' U {R2 L2} U2 F' L2 F U2 L U' L U L F' L' F U' - HTM = 41 moves QTM = [52 moves] STM = {40 moves} | I seem to be having a good streak with FMC so far: both times, I have had a 41-ish move solution on the second try. Here's this one: L D' R2 D2 : Cross L' U' R U R' : F2L pair one U2 L U' L U2 L' U' L U L' : F2L pair two R2 U2 R U R' U R2 : F2L pair three L2 U2 F' L2 F U2 : F2L pair four L U' L U L F' L' F U' : OLL with PLL skip |
[此贴子已经被作者于2004-10-30 23:29:47编辑过]
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