乌木 发表于 2005-11-10 21:09:14

<P>好吧,我临时抱佛脚,和您一起来看看第6楼内容。它说:</P>
<P>第3层第2步:角块归位法</P>
<P>先看个下图所示的第3层角块已归位的例子:</P>
<P><br></P>
<P>为了使四个角块都归位,同样只要一个公式,也可不用</P>
<P>对称转法,此公式即公式三:</P>
<P>R U' L' U R' U' L U2</P>
<P>此公式的效果仅仅就角块的位置来说,为 A 、B两角交换:</P>
<P></P>
<P>对于角块未归位的一个魔方,为了用公式三,先要识别</P>
<P>哪两个角块要求交换。6楼说,较方便的识别法为:</P>
<P>例一:</P>
<P></P>
<P>如上图,顶层四个角块一定都含有顶层的红色,而魔方的前</P>
<P>色(白)、右色(绿)、后色(黄)和左色(蓝)则分别只</P>
<P>有两个顶层角块所含有。上图标上标记后得下图,其中,</P>
<P>角块B、C含白,A、C含绿,A、D含黄,B、D含蓝。</P>
<P><br><br>现在要在相邻的两个角块上找出有没有除红色以外的、</P>
<P>相同的颜色。上图中,</P>
<P>角A、B无这样的相同色,</P>
<P>角A、D有这样的相同色(黄),</P>
<P>角C、D无这样的相同色,</P>
<P>角B、C有这样的相同色(白)。</P>
<P>我们取角A、D(都含黄)来判断它们是否要交换。为此,</P>
<P>顶层转180°,角A、D到了后面,因为后面是魔方黄色面</P>
<P>所在处,得到下图,再来判断A、D是否要交换。</P>
<P></P>
<P>显然,上图中角A、D已归位!而角B、C却要交换。</P>
<P>为了用公式三交换B、C,必须改变整个魔方的取向,即</P>
<P>保持红色中心块向上,让绿色中心块向前,见下图:</P>
<P><br><br>这样就成为蓝后,黄右,白左。而要交换的B、C角</P>
<P>到左边去了,与公式三的效果图一致,当然可以执行</P>
<P>公式三了。(乌木注,公式三的其它效果此处</P>
<P>不必管它!)最后结果如下图:</P>
<P></P>
<P>对6楼以下的内容可参考我上面对6楼的复述来看,</P>
<P>您得举一反三。<br></P>
[此贴子已经被作者于2005-11-11 10:57:57编辑过]

whlzero 发表于 2005-11-11 08:08:45

82187463 发表于 2005-12-13 21:16:13

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haibeidie 发表于 2006-1-3 03:05:39

haibeidie 发表于 2006-1-7 17:43:45

zkang 发表于 2006-1-8 23:06:37

<P>谢谢,菜鸟成功复原,正在努力记住这些公式。</P>

土豆 发表于 2006-1-25 18:04:14

回复44层的,可能是你的魔方有问题

土豆 发表于 2006-1-25 18:08:21

<P>我顶楼主的,本来我只会还原一个面(不包括侧边),现在我能照着还原6个面了~~~背公式中~~~………………</P>

乌木 发表于 2006-1-25 18:36:30

回56楼“土豆”兄,44楼<FONT face=Verdana color=#61b713><STRONG>whlzero</STRONG><FONT color=#000000>兄的魔方没问题,见52楼。</FONT></FONT>

土豆 发表于 2006-1-26 10:34:08

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查看完整版本: 公式较少的还原方法