例一:
[java4=400,400]
[param=scrptLanguage]SupersetENG[/param]
[param=scrpt]TU' R U R' CU R2 F R2 F' CU R U2 R' TU' CU2 /*第一个3*/ \n R U2 R' CU R U' R' CU /*遇到小循环*/ \n R U' R' CU TU2 R' D R TU CU /*解决小循环的方法,第二个3*/ \n F D F' CU R' D' R CU F D' F' TU' CU4 /*第三个3*/[/param]
[param=stickersFront]1,1,1,1,4,0,0,5,1,0,0,3,5,3,4,5[/param]
[param=stickersRight]0,5,5,3,4,1,1,5,2,1,1,2,1,5,0,4[/param]
[param=stickersDown]0,5,2,3,4,2,2,3,2,2,2,1,1,0,4,2[/param]
[param=stickersBack]2,4,1,4,1,3,3,0,3,3,3,5,0,0,1,0[/param]
[param=stickersLeft]5,0,4,5,5,4,4,3,4,4,4,2,5,0,2,4[/param]
[param=stickersUp]3,2,3,4,2,5,5,1,0,5,5,0,3,3,3,2[/param]
[/java4]
93法中的9完成后。3就被跳过了,其中的循环有两种方法处理:要么处理,要么不处理,听之任之,不过我个人比较建议先处理。这样的话很容易跳3的,只要做完9,3很可能会直接跳过
例二:
[java4=400,400]
[param=scrptLanguage]SupersetENG[/param]
[param=scrpt]TU' F' R' F R CU F D2 F' CU F R' F' R TU' CU2 /*第一个3*/ \n R' F R F' CU R' F R F' CU F R' F' R TU' CU2 /*第二个3*/ \n F' U' F CU F D' F' CU R F R' F' TU' CU4/*第三个3*/[/param]
[param=stickersFront]1,4,3,5,0,0,0,0,1,0,0,1,1,3,1,0[/param]
[param=stickersRight]3,3,4,0,2,1,1,0,0,1,1,0,1,4,4,4[/param]
[param=stickersDown]0,2,2,2,0,2,2,2,2,2,2,2,2,4,3,2[/param]
[param=stickersBack]5,5,5,5,5,3,3,3,2,3,3,1,0,1,3,3[/param]
[param=stickersLeft]1,5,0,3,2,4,4,5,5,4,4,3,4,1,4,5[/param]
[param=stickersUp]3,1,4,4,3,5,5,0,1,5,5,5,2,5,4,4[/param]
[/java4]
93法的9结束后,3又被跳过了,很无奈,只好举第三个例子,看能否不跳过。以上纯属打乱公式,无人为操控。
例三:
[java4=400,400]
[param=scrptLanguage]SupersetENG[/param]
[param=scrpt]TU' CU F D F' CU /*遇到小麻烦*/ \n F' R' U R F CU R U R' TU' CU2 /*第一个3*/ \n R' D' R CU R' F R F' CU F D' F' TU' CU2 /*第二个3*/ \n F D2 F' CU F D F' CU R' F R F' TU' /*第三个3*/ \n B TL F U' F' U TR' CU4/*93中的3*/[/param]
[param=stickersFront]1,1,3,5,0,0,0,4,2,0,0,3,0,4,0,5[/param]
[param=stickersRight]1,3,4,2,3,1,1,3,1,1,1,1,0,5,4,2[/param]
[param=stickersDown]2,0,2,4,0,2,2,4,2,2,2,2,3,1,0,3[/param]
[param=stickersBack]1,5,4,4,2,3,3,2,0,3,3,2,1,5,2,4[/param]
[param=stickersLeft]5,3,1,0,3,4,4,4,1,4,4,0,2,4,1,4[/param]
[param=stickersUp]3,5,0,0,1,5,5,3,5,5,5,5,5,5,5,3[/param]
[/java4]
终于没有跳3了,总的步骤就是这样,之前也有发过,只是讲的不是很明白,现在举个例子比较清晰,也有简介,如果还不明白请在LX回复
例四:
[java4=400,400]
[param=scrptLanguage]SupersetENG[/param]
[param=scrpt]L' TU' R U' R' CU2 F' U2 F TU' CU2 /*第一个3*/ \n L' U L R' D' R CU R' D' R CU F' U' F TU' CU2 /*第二个3*/ \n F' U2 F CU R U R' TU' /*第三个3完成,并且出现小循环*/ \n L2 TU SR U2 SR' TU' CU4/*解决小循环*/[/param]
[param=stickersFront]4,1,4,5,5,0,0,5,4,0,0,4,1,2,1,2[/param]
[param=stickersRight]4,3,4,4,3,1,1,4,0,1,1,4,0,3,3,4[/param]
[param=stickersDown]3,4,5,1,3,2,2,1,0,2,2,1,3,1,5,5[/param]
[param=stickersBack]2,1,5,0,0,3,3,2,5,3,3,2,3,1,2,1[/param]
[param=stickersLeft]1,2,0,2,0,4,4,0,0,4,4,5,5,1,4,2[/param]
[param=stickersUp]5,3,0,0,3,5,5,2,5,5,5,2,3,2,3,0[/param]
[/java4]