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<P>从最近的讨论中,看来,至少在下面的盲拧翻色例子中,做公式前后的调动路线和逆调动路线,可以不同于站长介绍的方法。第一图为非经过7号位的“正规方法”;第二图中,别去管非正规方法临时调到2号位的角块色向变了,认定最初编码时的翻色要求做,就毫无问题。</P>
<P> </P>
<applet code="RubikPlayer.class" codebase=3 width="320" height="270">
<param name="ColorTable" value="0xf8f8f8,0x00732f,0xff4400,0xffd200,0x003373,0x8c000f,0x858585">
<param name="scrptLanguage" value="SupersetENG">
<param name="scrpt" value="R2 D B2 ( L' U2 L U L' U L R U2 R' U' R U' R') B2 D' R2 \n R2 B2 ( R U R' U R U2 R' L' U' L U' L' U2 L ) B2 R2 ">
<param name="beta" value="29">
<param name="stickersFront" value="0,0,5,0,0,0,0,0,0">
<param name="stickersRight" value="0,1,3,1,1,1,1,1,1">
<param name="stickersBack" value="5,3,3,3,3,3,3,3,3">
<param name="stickersUp" value="5,5,1,5,5,5,5,5,1">
</applet>
<applet code="RubikPlayer.class" codebase=3 width="300" height="270">
<param name="ColorTable" value="0xf8f8f8,0x00732f,0xff4400,0xffd200,0x003373,0x8c000f,0x858585">
<param name="scrptLanguage" value="SupersetENG">
<param name="scrpt" value=" B ( L' U2 L U L' U L R U2 R' U' R U' R') B' \n R B( R U R' U R U2 R' L' U' L U' L' U2 L ) B' R' ">
<param name="beta" value="29">
<param name="stickersFront" value="0,0,5,0,0,0,0,0,0">
<param name="stickersRight" value="0,1,3,1,1,1,1,1,1">
<param name="stickersBack" value="5,3,3,3,3,3,3,3,3">
<param name="stickersUp" value="5,5,1,5,5,5,5,5,1">
</applet> |
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