********************** > But...wait...this scramble had oriented edges, right? well, for me not, 'cause an edge is oriented for me if it can reach solved position within R2, L2, U, D, F, B; and for you I think is F2, B2, L, R, U, D.. .or no? Yes, that's correct. One thing you could do is do a y-rotation after orientation and before permutation, but that could result in different headaches :-)
> well, this makes things a bit harder...for example...how would you solve FD -> LF? I'd do (D U2 F U2 D') M2 (D U2 F' U2 D')...but I think this is not a good idea...
You mean FL, not LF :-). And nah, you really just use B instead of U. And an x-rotation helps make it easy to twist. So for LF/FL I'd do:
[solve LF] (U' L' U) M2 (U' L U) [solve FL] x' (U L2 U') M2 (U L2 U') x The idea is always: - one move (out of U/U'/B/B') to get BU out of M - one move (out of L/L2/L'/R/R2/R') to replace it with the target we really want - undo that first of the three moves to get the real target into M There are of course a few exceptions but this is the general idea. Cheers! Stefan ********************** |