Stefan's M2 method

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http://games.groups.yahoo.com/group/blindfoldsolving-rubiks-cube/message/933

Ok, so here's my new method for permuting 3x3 edges, I call it "M2
method". It's very simple, fast, and 100% intuitive so you don't need
to learn a single alg for it.

Of course it's a 2-cycle method, one piece getting solved each time.
The piece to be solved is at FD. Since I can't just swap two pieces, I
need to have some side effect. Here it is swapping (FU,BD)+(U,D)+(F,B)
. Note FU and BD are solved relative to the M centers.

Here's an example solve, using scramble #28 from post #754 (http:
//tinyurl.com/lytqj). It's ready to be pasted into this page:
http://thearufam.brinkster.net/cube/wrapplet.asp

-------------------- start --------------------
[Scramble] U2 D2 L' U D2 R2 L2 D R D' B2 U D' F2 R2 U' F2 R2 B2

[solve LU] (L U' L' U) M2 (U' L U L')
[solve LD] (U' L2 U) M2 (U' L2 U)
[solve RF] (U R U') M2 (U R' U')
[solve RU] (R' U R U') M2 (U R' U' R)
[solve BD] M U2 M U2
[solve LF] (U' L' U) M2 (U' L U)
[solve RD] (U R2 U') M2 (U R2 U')
[solve FU] M U2 M U2
[solve RB] (U R' U') M2 (U R U')
[solve LB] (U' L U) M2 (U' L' U)
--------------------- end ---------------------

For M2 I use Joel's finger trick, i.e. L (l' M'), using my left ring
finger to pull the M'. My left middle finger holds the B stickers of
LB+LBD, so my ring finger is free for the M' and my index finger is
free for U'.

Oh, and actually it was a bad choice to have BU already solved. It's
the easiest to solve, it looks like:
[solve BU] M2

So, how do you like it?

Cheers!
Stefan

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转来论坛，解决棱块的步数也很少 例子中不过70来步。

大烟头

研究研究一下

[Scramble] U2 D2 L' U D2 R2 L2 D R D' B2 U D' F2 R2 U' F2 R2 B2

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呵，烟头发的java是怎么办到的？步骤放在一起看起来清晰多了。

大烟头

这M2方法，原理我还是不大明白，再发几个研究一下：

 

 

 

大烟头

看出一点眉目：

1、每个公式后加一步M2都是标准的棱块三置换公式。

2、左右两边的棱块归位都是从FD那个位置移过去的。

[em08]

yingmu

    我也看出些眉目，每个公式都只做了两个块、两个块的对调，然后再找出相应的第二个公式以达到不同的三循环的目的，我想两个公式可以任意搭配，做法相当精妙，这样只要记住少数几个公式搭配后就能成为不同的三循环；不过上面的实例色向上已经全都对了，如果能将色向的问题也考虑进去，这个方法潜力巨大。

    简单举例以下：

    比如上面提到的，第一个公式是FD和UL对调、UF和DB对调，第二个公式是LD和FD对调、UF和DB对调；这样通过两个公式的搭配就能实现FD-UL-LD-FD的三循环，UF和DB通过两次对调又回原位。

    如果角块也能有这样的公式就好了。

[此贴子已经被作者于2006-9-10 14:17:44编辑过]

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关于  M2 Method  的讨论

For blindsolving I'd probably use the full-cubie version (that'll be
my name for both permuting and orienting a cubie). It's very similar,
but instead of using U you use B, which should be done as U after cube
rotation, e.g.

[solve UR] x' (U' R U) M2 (U' R' U) x
[solve BR] (l U' R' U) M2 (U' R U l')

> I am not really sure if I understand how the M slice edges are
> handled... But it sure looks cool!

- FD is the buffer and thus ignored
- BU is solved with M2
- FU and BD are solved relative to the M centers
either with (M U2 M U2) or (U2 M' U2 M')

Cheers!
Stefan

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Oh crap... clarification: Of course you don't just use B *instead* of
U but you use it *additionally*.

And actually I'd like to call the full-cubie version "M2" and the
permute-only version "M2p". I just wanted to demonstrate M2p first
cause it's so extremely sweet to execute and might even get the
orient-first guys more interested :-)

Cheers!
Stefan

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