24.97秒记一副扑克&&对盲拧的启发。附时间拟合曲线

roundy

http://vimeo.com/6270043 很cool，感觉没有练习过的话 光搓开一遍整副扑克都不只25秒  ：）
并且脑袋晃得很过瘾，不知道是不是记忆高手都爱晃脑袋呢 !

[ 本帖最后由 roundy 于 2009-9-29 18:53 编辑 ]

[ 本帖最后由 一叶知秋 于 2010-1-23 02:03 编辑 ]

roundy

Ben Pridmore ，很厉害。 除了24.97秒记忆52张扑克，他半小时1800秒记忆的数字（number），二进制数（digit）都很厉害，下面是他在德国赛的成绩。  他用的是一套2704的字母表。 一个物体可以表示2张扑克（52×52=、或者3个十进制数（1000），或者10个二进制数（1024）。所以他记忆52张扑克实际只记忆26个物体（我称之为信元）

	number	digit	cards	speednum	cards
时间(秒)	1800	1800	1800	300	24.97
记忆数量	1193	3610	728	240	52
实际记忆信元数	397.6666667	361	364	80	26
每秒记忆信元数	0.220925926	0.200556	0.202222	0.266667	1.041249
每个信元用时（秒）	4.526404023	4.98615	4.945055	3.75	0.960385

可以看到同样是30分钟记忆的内容。二进制翻译得比较慢、扑克次之、10进制数转换的最快，但记忆的
信元数量很接近，在361-398之间，每个信元记忆时间要5秒左右。   而时间段的5分钟记忆，速度就提高了，
每个信元之需要3.75秒，52张扑克24.97秒就更快了。每个信元只需要0.96秒。一秒一个.
   盲拧一个3阶魔方大概要记忆20个块的情况，但是可以2个一组编码，大概是10个信元，包括奇偶、角棱原地反大概是11-12个信元。 时间大概也在11-12秒。要提高有几个方向：1.编码容量更大 2. 利用短时记忆  3.多种方式记忆。声音、形象、手脚摆放位置。
   对多盲来说，一个魔方复原大概30秒，记忆12组情况，大概5秒一组共60秒，那么应该90秒可以搞定一个，3600秒应该可以拧40个。（：）理论上而已）

附图是统计了ben的历次成绩后用excel函数拟合后的结果，y = 0.3374x0.3433   R² = 0.9824 ，y是每个信元记忆的时间，x是记忆的总时长。可以看到R平方已经有0.9824还是很准。

[ 本帖最后由 roundy 于 2009-9-29 11:18 编辑 ]

roundy

"中文版-BEN 記憶系統!世界排名第一的記憶系統! 中文版-BEN 記憶系統!世界排名第一的記憶系統!
        The 'Ben Pridmore System' 我的技巧並不是什麼秘密,我十分高興與各位分享, 上年,我常在wwbc公開這方法,但因我們在這有了新 的團體,那我會再公開它和會盡量簡單易明.我並沒 給它“”Ben system“這名字，但有很多人這樣稱它， 而我也喜歡這名稱． 這方法的基本原理與很多人使用的記法的相同的， 把表象放在腦海內各地點（地點法），但我不是同 人物＋動作＋物品這樣記的，我只是將三樣困‘’東西‘’ 一起放在同一地點，這些‘’東西‘’有些是人物，有些是 物品．我（想像）它們的排列是由左向右，或上向下 來分先後次序的，而它們之間會有相互作用自然發生． 每“”一物“”代表兩張撲克牌，或３個十位數字（如２３６，４５７）， 或十個二進位數字（００１１００００１０）．這一物 的名稱是由３個音節所組成的，子音＋母音＋子音＝一物． 以下是撲克的音節代碼：

第一個是子音，如下： Club＝梅花，Ｄiamond＝階磚，heart＝紅心，spade＝葵花．
club/club - k
club/diamond - t
club/heart - n
club/spade – m

diamond/club - r
diamond/diamond - d
diamond/heart - l
diamond/spade - g/j

heart/club ?f/th
heart/diamond - b
heart/heart - h
heart/spade – p

spade/club - sk/sn/sm
spade/diamond - st/sp
spade/heart - sh/sl/sw
spade/spade ?s

接著是母音，如下：
A = `a' as in `cat'
2 = 'e' as in 'pet'
3 = 'i' as in 'kitten'
4 = 'o' as in 'tom'
5 = 'u' as in 'puss'
6 = `A' as in `hay'
7 = `E' as in `bee'
8 = `I' as in `high'
9 = `O' as in `low'
10 = `oo' as in `you'
J = `ow' as in `cow'
Q = `or' as in `door'
K = `ar' as in `car'

最後是子音，如下：
A = t
2 = n
3 = m
4 = r
5 = l
6 = g
7 = k
8 = f/th
9 = b
10 = s
J = j/sh/ch
Q = p
K = d

例如：紅心Ａ＋梅花２＝（紅心＋梅花=f）＋ (a)Ａ＋ (ｎ)２ =fan(風扇).
又例如: (club+heart=n) + e (2) + t (Ace) = `net'(網).

這給了我2704個可同的物象. 數字上,我會使用相同的”物象”,但十位數字只需1000個代碼, 而二進制就需要1024個代碼.看下表: 第一個子音(第一個數字) 0 = s 1 = t 2 = n 3 = m 4 = r 5 = l 6 = gj 7 = k 8 = f/th 9 = b 母音(第二個數字) 0 = `oo' 1 = `a' 2 = 'e' 3 = 'i' 4 = 'o' 5 = 'u' 6 = `A' 7 = `E' 8 = `I' 9 = `O' 子音(第三個數字) 0 = s 1 = t 2 = n 3 = m 4 = r 5 = l 6 = g 7 = k 8 = f/th 9 = b 而二進制數字是這樣,如下: 首子音(首4個數字) 0000 = s 0001 = t 0010 = n 0011 = m 0100 = r 0101 = l 0110 = g/j 0111 = k 1000 = f 1001 = b 1010 = p 1100 = h 1101 = sk/sn/sm 1110 = st/sp 1111 = sh/sl/sw 母音(接著的三個數字) 000 = `oo' 001 = `a' 010 = 'e' 011 = 'i' 100 = 'o' 101 = 'u' 110 = `A' 111 = `E' 子音(最後三個數字) 000 = s 001 = t 010 = n 011 = m 100 = r 101 = l 110 = g 111 = k 我希望這足夠明白易懂.我非常歡迎回答來問! 我現在是否很久沒練撲克和二進位數字?在上年, 我沒有認真練習過,我在前三個月只集中精神記圓周率, 但我肯定我仍熟記以上的代碼,所以如果我再開始訓練, 我應該能夠很快可以運用以上的技巧,希望如此. BEN 原文: The 'Ben Pridmore System' My techniques aren't a secret, I'm quite happy to share them with anyone who's interested. I normally point people towards the wwbc posts last year where I explained it, but since we've got a brand new group here, I've rewritten it and made it hopefully a bit easier to understand. I don't actually call it the 'Ben system', but that's what some people have been calling it, and I do quite like the name. It's really just an extension of the basic Major system. The basic principle is the same as everyone else uses, visualising images at points along a mental route or journey. I don't use the person-action-object ideas of some people, I just have three `objects' at each point on my route. Some of these objects are people, some are things. I `see' them arranged from left to right, or top to bottom, and interacting in various ways according to rules I made up as I went along, depending on which objects come together in what order. Each object is made from a combination of two playing cards, or three decimal digits, or ten binary digits. The name of the object starts with a one-syllable sound made up of a consonant, a vowel and another consonant. For playing cards, these sounds are made as follows. The first consonant is given by the combination of suits, like this: club/club - k club/diamond - t club/heart - n club/spade - m diamond/club - r diamond/diamond - d diamond/heart - l diamond/spade - g/j heart/club ?f/th heart/diamond - b heart/heart - h heart/spade - p spade/club - sk/sn/sm spade/diamond - st/sp spade/heart - sh/sl/sw spade/spade ?s The vowel comes from the number/rank of the first card, like this: A = `a' as in `cat' 2 = 'e' as in 'pet' 3 = 'i' as in 'kitten' 4 = 'o' as in 'tom' 5 = 'u' as in 'puss' 6 = `A' as in `hay' 7 = `E' as in `bee' 8 = `I' as in `high' 9 = `O' as in `low' 10 = `oo' as in `you' J = `ow' as in `cow' Q = `or' as in `door' K = `ar' as in `car' And the final consonant comes from the number of the second card, like this: A = t 2 = n 3 = m 4 = r 5 = l 6 = g 7 = k 8 = f/th 9 = b 10 = s J = j/sh/ch Q = p K = d So, for example, Ace of hearts + 2 of clubs gives f (heart/club) + a (Ace) + n (2) = `fan'. If the 2 of clubs came first it would be n (club/heart) + e (2) + t (Ace) = `net'. That gives me 2704 different images. For numbers, I use the same list of images, but only use 1000 of them for decimal and 1024 for binary. It works like this: First consonant (first digit) 0 = s 1 = t 2 = n 3 = m 4 = r 5 = l 6 = gj 7 = k 8 = f/th 9 = b Vowel (second digit) 0 = `oo' 1 = `a' 2 = 'e' 3 = 'i' 4 = 'o' 5 = 'u' 6 = `A' 7 = `E' 8 = `I' 9 = `O' Second consonant (third digit) 0 = s 1 = t 2 = n 3 = m 4 = r 5 = l 6 = g 7 = k 8 = f/th 9 = b And for binary, it's: First consonant (first four digits) 0000 = s 0001 = t 0010 = n 0011 = m 0100 = r 0101 = l 0110 = g/j 0111 = k 1000 = f 1001 = b 1010 = p 1100 = h 1101 = sk/sn/sm 1110 = st/sp 1111 = sh/sl/sw Vowel (next three digits) 000 = `oo' 001 = `a' 010 = 'e' 011 = 'i' 100 = 'o' 101 = 'u' 110 = `A' 111 = `E' Second consonant (final three digits) 000 = s 001 = t 010 = n 011 = m 100 = r 101 = l 110 = g 111 = k I hope that's clear. I'm always happy to answer questions! I'm very out of practice with the cards and binary now ?I haven't really done any training since last year, and I've been concentrating on memorising pi for the last three months. I'm pretty sure I can still remember the list of images, so I should be able to just click back into the swing of it if I start training again, I hope. Ben "

[ 本帖最后由 roundy 于 2009-10-3 23:07 编辑 ]

Cielo

呃果然是看一遍就记下来了啊……

天花板上吊着猫

Cool，但我不会去学，因为会掉头发。。。= =

幽默菜

    太强了~~

一叶知秋

妙哇~！
盲拧正需要有这种基础作为保障的，看来要想提高盲拧成绩，单纯练习记忆也是必须的哦！

裸兰

好强悍，盲拧的记忆倒是可以参考。首页留名。

乌冬仔

顶顶先...很有用额..

三叶虫

重要的是他用的数表。。。太多了。。。想学习的同学不妨先到医疗服务区练习 手指操