急！请教一个K4最后一层交换2棱的问题！

hopeman

<P> </P>
<P>运用K4还原到最后一层结果出现了需要交换2棱的情况（如上图），</P>
<P>无法用交换3棱的方法解决了，</P>
<P>不知各位大大们有没有什么好办法？</P>
<P>估计有公式的但找不到：（</P>

klcd

R B - MR U2 MR U2 x U2 MR U2 TR' L U2 ML U2 MR2' - B' R'

hopeman

K4是某些魔方高手们研究出的一种4阶还原法，
其实就是层先法，
基本思路是这样：
完成6个中心>>底面十字>>F3L>>顶面4角>>顶面的棱归位>>顶棱翻色
（前两步的顺序目前还有不同的讨论，最后三步现在也有人开始研究4阶的OLL和PLL了）
与降阶法主要的区别就在于F3L和顶棱归位，
相对比较有意思吧，
拥护者也不少，
但目前拿世界排名的高手们更常用的还是降阶而不是K4，
因为步骤稍多所以速度慢些。
感兴趣的同志可以上youtube找找，
有很多K4的视频。
这里推荐一个，
我就是通过它学会K4的：）

http://www.youtube.com/watch?v=LqpJobHhlOg&feature=related

bbshanwei

K4法没有听说过，LZ能推荐一下吗？

三叶虫

<P><FONT color=#000000><SPAN lang=EN-US style="FONT-SIZE: 14pt; FONT-FAMILY: 'Times New Roman'; mso-fareast-font-family: 宋体; mso-font-kerning: 1.0pt; mso-ansi-language: EN-US; mso-fareast-language: ZH-CN; mso-bidi-language: AR-SA"> </SPAN></FONT></P>
<P><FONT color=#000000><SPAN lang=EN-US style="FONT-SIZE: 14pt; FONT-FAMILY: 'Times New Roman'; mso-fareast-font-family: 宋体; mso-font-kerning: 1.0pt; mso-ansi-language: EN-US; mso-fareast-language: ZH-CN; mso-bidi-language: AR-SA"></SPAN></FONT>&nbsp;</P>
<P><FONT color=#000000><SPAN lang=EN-US style="FONT-SIZE: 14pt; FONT-FAMILY: 'Times New Roman'; mso-fareast-font-family: 宋体; mso-font-kerning: 1.0pt; mso-ansi-language: EN-US; mso-fareast-language: ZH-CN; mso-bidi-language: AR-SA">R</SPAN><SPAN lang=EN-US style="FONT-SIZE: 14pt; FONT-FAMILY: 'Times New Roman'; mso-fareast-font-family: 宋体; mso-ansi-language: EN-US; mso-fareast-language: ZH-CN; mso-bidi-language: AR-SA"> MUU B</SPAN><SPAN lang=EN-US style="FONT-SIZE: 14pt; FONT-FAMILY: 'Times New Roman'; mso-fareast-font-family: BatangChe; mso-ansi-language: EN-US; mso-fareast-language: ZH-CN; mso-bidi-language: AR-SA">'</SPAN><SPAN lang=EN-US style="FONT-SIZE: 14pt; FONT-FAMILY: 'Times New Roman'; mso-fareast-font-family: 宋体; mso-ansi-language: EN-US; mso-fareast-language: ZH-CN; mso-bidi-language: AR-SA"> D2 B MUU</SPAN><SPAN lang=EN-US style="FONT-SIZE: 14pt; FONT-FAMILY: 'Times New Roman'; mso-fareast-font-family: BatangChe; mso-ansi-language: EN-US; mso-fareast-language: ZH-CN; mso-bidi-language: AR-SA">'</SPAN><SPAN lang=EN-US style="FONT-SIZE: 14pt; FONT-FAMILY: 'Times New Roman'; mso-fareast-font-family: 宋体; mso-ansi-language: EN-US; mso-fareast-language: ZH-CN; mso-bidi-language: AR-SA"> B</SPAN><SPAN lang=EN-US style="FONT-SIZE: 14pt; FONT-FAMILY: 'Times New Roman'; mso-fareast-font-family: BatangChe; mso-ansi-language: EN-US; mso-fareast-language: ZH-CN; mso-bidi-language: AR-SA">'</SPAN><SPAN lang=EN-US style="FONT-SIZE: 14pt; FONT-FAMILY: 'Times New Roman'; mso-fareast-font-family: 宋体; mso-ansi-language: EN-US; mso-fareast-language: ZH-CN; mso-bidi-language: AR-SA"> (MLL</SPAN><SPAN lang=EN-US style="FONT-SIZE: 14pt; FONT-FAMILY: 'Times New Roman'; mso-fareast-font-family: BatangChe; mso-ansi-language: EN-US; mso-fareast-language: ZH-CN; mso-bidi-language: AR-SA">'</SPAN><SPAN lang=EN-US style="FONT-SIZE: 14pt; FONT-FAMILY: 'Times New Roman'; mso-fareast-font-family: 宋体; mso-ansi-language: EN-US; mso-fareast-language: ZH-CN; mso-bidi-language: AR-SA"> B2) 4 MLL</SPAN><SPAN lang=EN-US style="FONT-SIZE: 14pt; FONT-FAMILY: 'Times New Roman'; mso-fareast-font-family: BatangChe; mso-ansi-language: EN-US; mso-fareast-language: ZH-CN; mso-bidi-language: AR-SA">'</SPAN><SPAN lang=EN-US style="FONT-SIZE: 14pt; FONT-FAMILY: 'Times New Roman'; mso-fareast-font-family: 宋体; mso-ansi-language: EN-US; mso-fareast-language: ZH-CN; mso-bidi-language: AR-SA"> D2 B R</SPAN><SPAN lang=EN-US style="FONT-SIZE: 14pt; FONT-FAMILY: 'Times New Roman'; mso-fareast-font-family: BatangChe; mso-ansi-language: EN-US; mso-fareast-language: ZH-CN; mso-bidi-language: AR-SA">'</SPAN></FONT></P>

乌木

我也不知什么叫K4法，所以给出10楼方法仅供参考。

apmkeke

不懂   但是 支持 一下加油

kexin_xiao

LZ说的那个方法叫K4吗？不太明白。乌木老师给的公式可以一步完成。

乌木

<P>10楼方法以前“偶尔路过”教过，这次开始没想起来，弄了个9楼的方法。不是9楼方法不好，而是用于此题不好。如果遇到下面情况，就适用了：</P>
<P>&nbsp;</P>
<applet code="RevengePlayer.class" codebase=4 width="300" height="300">
<param name="colortable" value="0xf8f8f8,0x00732f,0xff4400,0xffd200,0x003373,0x8c000f,0x858585">
  <param name="scrptLanguage" value="SupersetENG">
  <param name="scrpt" value="TL F2 D MF D' F2 D MF' D' TL' ">
  <param name="scriptProgress" value="0">
  <param name="beta" value="29">
  <param name="stickersFront" value="0,1,5,0,0,0,0,0,0,0,0,0,0,0,0,0">
  <param name="stickersRight" value="1,5,1,1,1,1,1,1,1,1,1,1,1,1,1,1">
  <param name="stickersUp" value="5,5,5,5,5,5,5,5,5,5,5,0,5,5,0,5">
</applet>

[ 本帖最后由 乌木 于 2008-7-24 09:19 编辑 ]

乌木

<P>这大概算一式完成方法了：</P>
<P>&nbsp;</P>
<applet code="RevengePlayer.class" codebase=4 width="300" height="300">
<param name="colortable" value="0xf8f8f8,0x00732f,0xff4400,0xffd200,0x003373,0x8c000f,0x858585">
  <param name="scrptLanguage" value="SupersetENG">
  <param name="scrpt" value=" R B CR2 ((ML' U2 )4 ML' U MF' U' F2 U MF U' F )  R' ">
  <param name="scriptProgress" value="0">
  <param name="beta" value="29">
  <param name="stickersFront" value="1,2,1,1,1,1,1,1,1,1,1,1,1,1,1,1">
  <param name="stickersRight" value="2,1,2,2,2,2,2,2,2,2,2,2,2,2,2,2">
  <param name="stickersDown" value="0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0">
  <param name="stickersBack" value="4,4,4,4,4,4,4,4,4,4,4,4,4,4,4,4">
  <param name="stickersLeft" value="5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5">
  <param name="stickersUp" value="3,3,3,3,3,3,3,3,3,3,3,3,3,3,3,3">
</applet>