大家多交流一下extend cross的经验

gozichen

经过一段练习后，相信大家对在15s内观察出8步拧出cross不是什么
太大问题，下一个目标是在10步做出extend cross，但魔友好象在这方面交流得不多。
这是Chris Hardwick对怎样练习extend cross的方法介绍：（虽然是英文，但不是很难理解，大家自己看看吧）
希望大家多交流交流。

有兴趣可以去http://www.speedcubing.com/chris/ec-strategy.html看看

简单地翻译一下：
1.先练习先用最少的步骤组合一个2*2*2
1）组成2*1*1（一个棱块和一个角块）
2）在1）的基础上组成2*2*1（两个棱块和一个角块）
3）在2）的基础上组成2*2*2
2.把组成的2*2*2和余下的棱块完成extend cross
3.熟悉了1.2步骤后，尝试缩短中间步骤而直接解决extend cross

不知道对不对，请高手指正。


How to solve the extended cross

If you've made it to this page then I assume you're interested in learning some of the strategies for seeing these extended cross solves. This page is an attempt to present some of the main strategies I use when looking for the shortest extended cross solve.
The 2x2x2
If you, like I was when I first tried this method out, have only ever done "cross" methods then chances are you're very unfamiliar with solving the 2x2x2. If you already use a 2x2x2 system then go on to the next section. So if you have only ever solved the cross, or some other method, then you will want to familiarize yourself with solving the 2x2x2. Some basic strategy for doing this is to 1) form a 2x1x1; 2) form a 2x2x1 out of the piece create in #1; 3) form a 2x2x2 out of the piece created in #2. Here is an example,
Here we have only the pieces necessary to form the 2x2x2. We can solve the 2x2x2 from this particular position in 6 moves. If you can see this solution that's great! If not, then let's step through it. For each step use the "original position" cube to try to follow along and see how each step relates to the original position. If you click on a center piece of a face you can even do the same moves on the original position cubes. Hold down alt while clicking to rotate the opposite direction. For each step, the cube in the right column starts in the final position as the previous right column cube, only with a new piece added each time. This way you can see the step-by-step approach I take to figuring out how to solve a 2x2x2.
It should now be fairly obvious what the strategy is to solving the 2x2x2. First you want to try to find the fewest number of moves to put together a 2x1x1. Once you find one, can you find an easy way to extended your 2x1x1 into a 2x2x1? If not, then try to go back and choose another pair to build your 2x1x1. Once you find a 2x1x1 that easily extends into a 2x2x1, try to find a way to place the last edge to form your 2x2x2. Once you have a solution, try to find ways to do two things at once. Use the above example as an idea. We were able to form the 2x2x1 and place the last edge all in one move, leaving the last turn to just simply form the 2x2x2 by lining up the two pieces. This extends as a general rule. Once you have your solution, can you combine steps to help shorten the number of moves? Later you may find other ways on your own to solving the 2x2x2, the way suggested here is certainly not the only way, it is just a good way to try and get started if you have previously no experience with the 2x2x2.
Extension from 2x2x2 into extended cross

By now you should be fairly comfortable with solving a 2x2x2 on your own if you were not originally accustomed to it. Now what you want to try to do is to solve the 2x2x2 while paying attention to the other two edges of the first layer. A beginning strategy to this step is to try to find the shortest solution to the 2x2x2, that you would use if you were ignoring those other two edges. Then go through that solution in your head and see if the moves will put the edges in a bad position. A "bad position" is one that will take generally around 5 moves to solve the last two edges, in addition to the number of moves it took you to do the 2x2x2. So you can see if you get a 7 or 8 move 2x2x2 and you have a 5 move position for the last two edges, then you've now done 12-13 moves on the extended cross, which though not terrible, is not that great either. What you want to do is end up in a position where it may take only 2-3 moves. Later you can try to extend to solving the 2x2x2 and one edge as a direct solve, while paying attention to the last edge and therefore trying to get it into a "good" position after completing the 2x2x2 and one edge. These are all good strategies to use all the time, since sometimes solving the 2x2x2 and then the last remainging edge or edges is indeed the fastest way. However, don't limit yourself to using this strategy every time.
Direct solving the extended cross:
If you really want to learn the extended cross method in a way that will truly be useful to you later, you have to learn to direct solve it. Basically all I can say about this step is that you have to become so familiar with the process of following all 6 pieces in your head that it becomes just as easy to solve the extended cross as it does the cross, or the 2x2x2 for you. Naturally it will always be a little bit more difficult because there are 6 pieces instead of 4, however I've noticed that when I've practiced extended cross solves a lot I can usually see a decent solution (around 10-11) moves for most all scrambles. This method is still in the works, but my eventual goal is to average under 10 moves for each scramble, and to be able to do these solves smoothly going "slow-fast" during the F2L. If I come up with any new ideas I'll post them, but so far you know now as much as I know about the process. The rest comes with practice and determination. I hope these pages have helped you understand the extended cross method if you're interested, or at least cleared it up for you if you're not. If you have any more questions or comments then feel free to e-mail me at foozman17@hotmail.com

[ 本帖最后由 铯_猪哥恐鸣 于 2009-2-23 18:58 编辑 ]

潼哥哥

让我们这种小学森怎么办？

989812121289

额  顶一个                        

742774804

经过一段练习后，相信大家对在15s内观察出8步拧出cross不是什么
太大问题，下一个目标是在10步做出extend cross，但魔友好象在这方面交流得不多。
这是Chris Hardwick对怎样练习extend cross的方法介绍：（虽然是英文，但不是很难理解，大家自己看看吧）
希望大家多交流交流。 有兴趣可以去http://www.speedcubing.com/chris/ec-strategy.html看看 简单地翻译一下：1.先练习先用最少的步骤组合一个2*2*2 1）组成2*1*1（一个棱块和一个角块）2）在1）的基础上组成2*2*1（两个棱块和一个角块）3）在2）的基础上组成2*2*2 2.把组成的2*2*2和余下的棱块完成extend cross 3.熟悉了1.2步骤后，尝试缩短中间步骤而直接解决extend cross 不知道对不对，请高手指正。How为了解决扩展交叉
















如果你已经做到了这页，然后我假设你有兴趣学习一些策略的看到这些扩展的交叉求解。此页面是为了介绍一些我用的时候看的最短扩展的主要策略交叉解决。
的2x2x2的
如果你像我，当我第一次尝试这种方法了，只做过“ 交叉 “的方法然后有机会你很陌生解决2x2x2的。如果您已经使用一个2x2x2的系统，然后继续下一部分。所以，如果你已经永远只能解决了交叉，或其他一些方法，那么你将要熟悉解决2x2x2的。这样做的一些基本策略是：1）形成一个2x1x1; 2）形成一个2×2×出一块建立在＃1，3）形成一个2x2x2的列＃2中创建的一块。下面是一个例子，
在这里，我们只需要在片形成2x2x2的。我们可以从这个特殊的位置，解决了2×2× 6的动作。如果你能看到这个解决方案，这是伟大的！如果没有，那么让我们来看它。对于每个步骤使用的“原始位置”立方体来尝试跟随并了解每个步骤涉及到原来的位置。如果你点击一个中心部分的一张脸，你甚至可以做原来的位置立方体同样的动作。按住Alt键的同时单击旋转方向相反。对于每个步骤，在右列中的立方体开始在最后的位置与前面的右列的立方体，只用一块新的每次添加。这样你可以看到一步一步的方法，我需要搞清楚如何解决一个2x2x2的，
现在应该是相当明显的策略是解决2x2x2的是什么。首先，你要试图找出最少的动作放在一起2x1x1。一旦你找到了，你可以找到一个简单的方法来扩展你的2x1x1成2×2×？如果没有，那么尝试返回并选择另一对建立你2x1x1。一旦你找到一个2x1x1，很容易扩展成2×2×，试图找到一种方法，把最后的边缘，形成你的2x2x2的。一旦你有一个解决办法，尽量想办法做两件事情。使用上面的例子作为一个想法。我们能够形成2×2× 和放置在最后一个边沿都在同一个举动，剩下最后轮到只是简单地通过排队两片形成的2x2x2的。这个扩展作为一般规则。一旦你有你的解决方案，您可以结合步骤，以帮助缩短移动的号码吗？以后你可能会发现其他的方法你自己去解决的2x2x2，顺便建议在这里肯定不是唯一的方法，它仅仅是一个很好的方式，试图上手，如果你有以前没有的2x2x2的。经验
支线2x2x2的成延伸交叉

到现在，你应该很熟悉你自己解决一个2x2x2的，如果你原本不是习惯了。现在你想尝试做的是解决2x2x2的同时注意第一层的另外两个边。A开头的战略到这一步，试图找到最短的解决2x2x2的，你会使用，如果你忽略了与其他两条边。然后通过在你的脑袋该解决方案，看看是否移动将会把边缘处在倒霉的位置。“坏姿势”是一个将采取一般在5移动解决最后两个边，除了招式花了你做的2x2x2的数量。所以，你可以看到，如果你得到一个7或8的举动2x2x2的，你必须在过去两年边缘的5招位置，那么你现在已经做了12-13的移动扩展的交叉，这虽然并不可怕，是不是很大无论是。你想要做的是最终在一个位置，它可能只需要2-3个动作。以后你可以尝试扩展到解决的2x2x2和一个边缘作为直接解决，同时注意最后的边缘，因此试图完成的2x2x2和一个边缘后把它转换成一个“好”的位置。这些都是很好的战略，利用所有的时间，因为有时解决2x2x2的，然后最后remainging边缘或边缘的确是最快的方法。但是，不要限制自己使用这种策略的每一次。
直销解决扩展的交叉：
如果你真的想学习扩展交叉法的方式，将真正对你有用以后，你要学会直接解决它。基本上所有我可以说这一步是，你必须要变得如此熟悉，下面所有的6个在你的脑袋，它只是变得容易解决了扩展的过程中交叉因为它的交叉，或2x2x2的为您服务。当然它总是会比较困难一点，因为有6个而不是4个，但我注意到，当我练延伸交叉解决了很多我通常可以看到一个体面的解决办法（约10-11），用于移动最重要的是打乱。这种方法仍然在工作，但我的最终目标是平均10岁以下的动作每个争夺，并且能够做到这些方法都无法解决进展顺利“慢-快”的F2L期间。如果我想出什么新的想法我会后他们，但到目前为止，你知道现在像我了解的过程。而其余部分则用实践和决心。我希望这些网页都有助于你理解了扩展的交叉方法，如果你有兴趣，或至少清除它适合你，如果你不是。如果您有任何问题或意见，然后随时给我发e-mail给我在foozman17@hotmail.com

与魔为友

看不懂。。。。。。。。。。。。。。。。。。。。。。。

Faithf

嗷……看不懂！六级还没过……

slt921118

貌似微凉想研究X-层先~~~X-CROSS是属于中岛等非人类使用的

哈还

刚学extend-cross，观察的时间比扭的时间还要长。平均做完十字架还有一组f2l用了12步，这样不熟练的话，我还是不用了。

牧野

英语放下几年了都，谁翻译下？

lily748

好难啊，高手教教我！