『视频』二阶单次WR 0.69s

r_517

Trentin Open 2011上，意大利人Christian Kaserer以0.69秒完成这个四步的打乱。U' F' R' U



的确这是一个幸运的打乱，但是幸运不等于作弊。不要再秀下限地说因为打乱步数少所以就是作弊这种幼稚的话。Erik的七步还原算不算幸运？Rowe的五步还原算不算幸运？还原步骤短不代表你能在15秒内观察出最短步数。观察出最短步数不代表你能在比赛的压力下在0.96秒内完成这个还原。这和某些错误打乱引发的所谓争议是完全两个性质。

cjc951212

观察强大
............

佐耳

好淡定。。。。。。。。。。。

鱼香ROSE

淡定帝  幸运儿。。。

小柒、

8楼那货是来秀智商下限的。。。

kimimcfly

果然很强大！高手的风采！

zqp2009

破二阶WR的概率更小了~~~

塞翁

哥伦布向西走！。           。

铯_猪哥恐鸣

转一段。。

Usually we print a lot of scramble papers an then, when comes to scamble, pick up one randomly and use it for that round/group so there is no way to know which scramble sheet will be in final, semi, etc.
BUT, even if a delegate would choose scramble for each group there won't be way to know if you are getting a lucky scramble from that solves. The delegate should have to scramble all the cubes, even the one he's suppose to compete with, and then decide. Of course THIS is unfair.
Even from 20 moves 2x2 scramble you can get 4 moves solve.
The program by WCA was made to make random scrambles. So we click on the "Scramble" button, print them, then randomly pick them up when comes to scramble. The scramble are read in the moment all the competitors are already in the waiting area, waiting for the cubes. Probably even the delegate. What should the scramble guy do? Go ask to the delegate to check the scramble, of his group, cuz they're too easy? No way.
Lucky scrambles are the part of the game, the computer generates them. I don't see why a delegate should CHECK the scrambles, the computer already checked them when generated.
If the computer generated scrambles are the problem, invent a generator with no lucky scrambles.

铯_猪哥恐鸣

国内发生过同样的事情，只不过当场没几个人看出打乱那么简单罢了。