全部是初级操作的角先法（遍历整个论坛没发现比我的更简单的！）

清衫小白

<P class=MsoNormal style="MARGIN: 0cm 0cm 0pt"><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'"><FONT color=#000000>第一步：上层角块全部还原，过于简单，不介绍。</FONT></SPAN></P>
<P class=MsoNormal style="MARGIN: 0cm 0cm 0pt"><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'"><FONT color=#000000>第二步：下层两角块位置互换</FONT></SPAN></P>
<P class=MsoNormal style="MARGIN: 0cm 0cm 0pt"><FONT color=#000000><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">左下角与右下角互换：（FDF<FONT face="Times New Roman">'</FONT>D<FONT face="Times New Roman">'</FONT></SPAN><SPAN lang=EN-US><FONT face="Times New Roman">）（R'D'R</FONT></SPAN><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">）</SPAN></FONT></P>
<P class=MsoNormal style="MARGIN: 0cm 0cm 0pt"><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'"><FONT color=#000000>解释：就是将右上角块移至右下位置，然后再用另一个方法移回去。此方法最多运用两次就可将下层角块位置复原。</FONT></SPAN></P>
<P class=MsoNormal style="MARGIN: 0cm 0cm 0pt"><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'"><FONT color=#000000>第三步：下层三角块颜色复原</FONT></SPAN></P>
<P class=MsoNormal style="MARGIN: 0cm 0cm 0pt"><FONT color=#000000><SPAN lang=JA style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'; mso-fareast-language: JA">三角块同时原地顺时针旋转</SPAN><SPAN lang=EN-US style="mso-fareast-language: JA"><FONT face="Times New Roman">90</FONT></SPAN><SPAN lang=JA style="FONT-FAMILY: 宋体; mso-fareast-language: JA">゜</SPAN><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">：将不旋转的角块置于右下角位置，(RBLF)(RBLF)(RBLF)</SPAN></FONT></P>
<P class=MsoNormal style="MARGIN: 0cm 0cm 0pt"><FONT color=#000000><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">解释：此方法最多运用两次就可完成全部角块复原工作。不再提示逆时针操作，不怕麻烦就连拧</SPAN><SPAN lang=EN-US><FONT face="Times New Roman">24</FONT></SPAN><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">下。</SPAN></FONT></P>
<P class=MsoNormal style="MARGIN: 0cm 0cm 0pt"><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'"><FONT color=#000000>第四步：边块还原</FONT></SPAN></P>
<P class=MsoNormal style="MARGIN: 0cm 0cm 0pt"><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'"><FONT color=#000000>边块还原一般可以先将魔方的第二层还原，然后是第一层，再复原第三层。</FONT></SPAN></P>
<P class=MsoNormal style="MARGIN: 0cm 0cm 0pt"><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'"><FONT color=#000000>这里只提供一个初级公式，只要不在乎时间还原整个魔方是没有任何问题的。</FONT></SPAN></P>
<P class=MsoNormal style="MARGIN: 0cm 0cm 0pt"><FONT color=#000000><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">如图，欲将前下方的边块移至前上位置，操作步骤：(L<FONT face="Times New Roman">'</FONT>RF</SPAN><SPAN lang=EN-US><FONT face="Times New Roman">2</FONT></SPAN><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">LR<FONT face="Times New Roman">'</FONT>D2)</SPAN><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">，此时后下位置的边块会发生移动。为此一般需要将一块没用的边块移到该位置，这样就会使得未还原的边块越来越少，直至还原整个魔方。</SPAN></FONT></P>
<P class=MsoNormal style="MARGIN: 0cm 0cm 0pt"><FONT color=#000000><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">如果你用了</SPAN><SPAN lang=EN-US><FONT face="Times New Roman">ABC</FONT></SPAN><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">几步将没用的边块移到后下位置，整个操作步骤为</SPAN><SPAN lang=EN-US><FONT face="Times New Roman">ABC(<FONT face=宋体>L<FONT face="Times New Roman">'</FONT>RF<SPAN lang=EN-US><FONT face="Times New Roman">2</FONT></SPAN><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">LR<FONT face="Times New Roman">'</FONT>D2</SPAN></FONT>)</FONT></SPAN><SPAN lang=EN-US><FONT face="Times New Roman">C-B-A-</FONT></SPAN><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">；有时前下边块与后下边块式同时到位的；只剩下三个边块时，通常会有两种方法，正确的方法能够还原整个魔方，错误的方法会剩下两块需要原地翻身（请注意观察一下后下边块的方向）。</SPAN></FONT></P>
<P class=MsoNormal style="MARGIN: 0cm 0cm 0pt"><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'"><FONT color=#000000>两边块原地翻身的办法：两块互换，产生三个不到位的边块，利用上述操作寻找正确的方法。</FONT></SPAN></P>

[ 本帖最后由 清衫小白 于 2008-6-7 13:53 编辑 ]

鱼儿水中游

发的是什么呀

simpldz

hao ding<IMG alt="" src="http://bbs.mf8-china.com/images/smilies/default/biggrin.gif" border=0 smilieid="3">

522063141

希望全部都有圖..
不然不太懂.

清衫小白

<applet codebase= "java/" code="RubikSeqViewer.class" archive="rubikseqviewer.jar" width="280" height="332">
<param name="author" value="Jiuzhao Hua">
<param name="contact" value="hua_jz@hotmail.com">
<param name="update_url" value="http://www.geocities.com/hua_jz/">
<param name="delay" value="20">
<param name="label_on" value="0">
<param name="editable" value="0">
<param name="degree" value="3">
<param name="color_config" value="D(255,255,0) R(0,0,255) U(255,255,255) F(255,0,0) L(0,255,0) B(255,128,0) G(168,168,168)">
<param name="color_0" value="FRUFDFLUR">
<param name="color_1" value="UULUBRUBU">
<param name="color_2" value="BLUUFFFLR">
<param name="color_3" value="LBRBBLFRD">
<param name="color_4" value="RFFLDRDDL">
<param name="color_5" value="DBRDBDBLD">
<param name="sequence" value="U R U' R' L F2 R L' U2 U R' U'">
</applet>

[ 本帖最后由 清衫小白 于 2008-6-7 15:37 编辑 ]

清衫小白

<applet codebase= "java/" code="RubikSeqViewer.class" archive="rubikseqviewer.jar" width="280" height="332">
<param name="author" value="Jiuzhao Hua">
<param name="contact" value="hua_jz@hotmail.com">
<param name="update_url" value="http://www.geocities.com/hua_jz/">
<param name="delay" value="20">
<param name="label_on" value="0">
<param name="editable" value="0">
<param name="degree" value="3">
<param name="color_config" value="D(255,255,0) R(0,0,255) U(255,255,255) F(255,0,0) L(0,255,0) B(255,128,0) G(168,168,168)">
<param name="color_0" value="FRUFDFLUR">
<param name="color_1" value="UULUBRUBU">
<param name="color_2" value="BLUUFFFLR">
<param name="color_3" value="LBRBBLFRD">
<param name="color_4" value="RFFLDRDDL">
<param name="color_5" value="DBRDBDBLD">
<param name="sequence" value="D' U L' U' D F2 U D' L2 L U' D">
</applet>

清衫小白

<applet codebase= "java/" code="RubikSeqViewer.class" archive="rubikseqviewer.jar" width="280" height="332">
<param name="author" value="Jiuzhao Hua">
<param name="contact" value="hua_jz@hotmail.com">
<param name="update_url" value="http://www.geocities.com/hua_jz/">
<param name="delay" value="20">
<param name="label_on" value="0">
<param name="editable" value="0">
<param name="degree" value="3">
<param name="color_config" value="D(255,255,0) R(0,0,255) U(255,255,255) F(255,0,0) L(0,255,0) B(255,128,0) G(168,168,168)">
<param name="color_0" value="FRUFDFLUR">
<param name="color_1" value="UULUBRUBU">
<param name="color_2" value="BLUUFFFLR">
<param name="color_3" value="LBRBBLFRD">
<param name="color_4" value="RFFLDRDDL">
<param name="color_5" value="DBRDBDBLD">
<param name="sequence" value="D' R' D' L' R F2 L R' D2 D R D">
</applet>

清衫小白

<param name="contact" value="hua_jz@hotmail.com">
<param name="update_url" value="http://www.geocities.com/hua_jz/">
<param name="delay" value="20">
<param name="label_on" value="0">
<param name="editable" value="0">
<param name="degree" value="3">
<param name="color_config" value="D(255,255,0) R(0,0,255) U(255,255,255) F(255,0,0) L(0,255,0) B(255,128,0) G(168,168,168)">
<param name="color_0" value="FRUFDFLUR">
<param name="color_1" value="UULUBRUBU">
<param name="color_2" value="BLUUFFFLR">
<param name="color_3" value="LBRBBLFRD">
<param name="color_4" value="RFFLDRDDL">
<param name="color_5" value="DBRDBDBLD">
<param name="sequence" value="D' R' D' L' R F2 L R' D2 D R D">
</applet>

清衫小白

<param name="contact" value="hua_jz@hotmail.com">
<param name="update_url" value="http://www.geocities.com/hua_jz/">
<param name="delay" value="20">
<param name="label_on" value="0">
<param name="editable" value="0">
<param name="degree" value="3">
<param name="color_config" value="D(255,255,0) R(0,0,255) U(255,255,255) F(255,0,0) L(0,255,0) B(255,128,0) G(168,168,168)">
<param name="color_0" value="FRUFDFLUR">
<param name="color_1" value="UULUBRUBU">
<param name="color_2" value="BLUUFFFLR">
<param name="color_3" value="LBRBBLFRD">
<param name="color_4" value="RFFLDRDDL">
<param name="color_5" value="DBRDBDBLD">
<param name="sequence" value="D' R' D' L' R F2 L R' D2 D R D">
</applet>

lyc12345

有难度啊~~~~~~~~~~~~~