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与其说“……本求解器便可以一步一步的教你完成整个魔方的六面还原……”,还不如说看它演示一下而已。这类求解器大多如此。照着它(们)的复原步骤做不会错,是需要复原但一时不会复原时的有用工具,以免不得不拆开重装法求得复原态。靠着它(们)获得了复原态之后,或接着做某种花样,或接着琢磨别的问题。靠它(们)学复原方法,一般是不容易的,因为,我想,它的复原思路不会和通常复原法一样的吧。下面对比一下,可以看出它对付复杂情况是特长,对付简单情况就反而不利索了。
<applet code="RubikPlayer.class" codebase=3 width="300" height="300">
<param name="scrptLanguage" value="SupersetENG">
<param name="stickersFront" value="1,1,1,1,0,1,1,1,1">
<param name="stickersRight" value="5,5,5,5,1,5,5,5,5">
<param name="stickersDown" value="3,3,3,3,2,3,3,3,3">
<param name="stickersBack" value="4,4,4,4,3,4,4,4,4">
<param name="stickersLeft" value="2,2,2,2,4,2,2,2,2">
<param name="stickersUp" value="0,0,0,0,5,0,0,0,0">
<param name="scrpt" value="R'L U'D F'B R'L ">
</applet>
<applet code="RubikPlayer.class" codebase=3 width="300" height="300">
<param name="scrptLanguage" value="SupersetENG">
<param name="stickersFront" value="1,1,1,1,0,1,1,1,1">
<param name="stickersRight" value="5,5,5,5,1,5,5,5,5">
<param name="stickersDown" value="3,3,3,3,2,3,3,3,3">
<param name="stickersBack" value="4,4,4,4,3,4,4,4,4">
<param name="stickersLeft" value="2,2,2,2,4,2,2,2,2">
<param name="stickersUp" value="0,0,0,0,5,0,0,0,0">
<param name="scrpt" value="CU' R L' F U R L' TD2 F2 TD2 R2 TD2 B2 TD2 L2 CU R U R' CU' R U R' CU2 R U R' TD' R U R' R U' R' TD' L' U L TD CU' L' U L TD R U' R' TD2 CU2 L' U L TD R U' R' TD2 R U' R' TD' L' U L CU' R' U' F' U F R CU L' R U' L U R' U' L' U L CU' R U R' U R U2 R' CU2 L' U' L U' L' U2 L R' U' R U' R' U2 R CU R U R' U R U2 R' CU L U L' U L U2 L' CU' L' U' L U' L' U2 L ">
</applet> |
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