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<P> 現在講的是第一層角的還原..做完十字後我們如果放在頂層的話..那麼還原角的公式都是R和D的組合..這樣根本很難用到手法去快速轉動..有兩個選擇..一是把十字放在左邊..或者是把十字放在底層..把公式轉換成R和U的組合..對此我的看法是..如果把十字放底層那麼還原角塊時魔方的整體轉動是U或U'..而如果把十字放在左邊..那麼魔方的整體轉動會是R或R'..而我覺得整體轉動時R或R'會更順手..所以我做完十字後就把它放在左邊然後才還原四個角..</P>
<P> 角的還原不外乎以下五種: </P<P> </P>
<applet code="RubikPlayer.class" codebase=3 width="250" height="250">
<param name="scrptLanguage" value="SupersetENG">
<param name="scrpt" value="U'R'U">
<param name="stickersFront" value="6,6,0,0,0,6,0,6,6">
<param name="stickersRight" value="5,6,6,6,6,6,6,6,6">
<param name="stickersDown" value="2,6,6,2,2,6,2,6,6">
<param name="stickersBack" value="6,6,3,6,3,3,6,6,3">
<param name="stickersLeft" value="4,4,6,4,4,4,4,4,4">
<param name="stickersUp" value="5,6,6,5,5,6,6,6,4">
</applet> <applet code="RubikPlayer.class" codebase=3 width="250" height="250">
<param name="scrptLanguage" value="SupersetENG">
<param name="scrpt" value="R'U'RU">
<param name="stickersFront" value="6,6,4,0,0,6,0,6,6">
<param name="stickersRight" value="0,6,6,6,6,6,6,6,6">
<param name="stickersDown" value="2,6,6,2,2,6,2,6,6">
<param name="stickersBack" value="6,6,3,6,3,3,6,6,3">
<param name="stickersLeft" value="4,4,6,4,4,4,4,4,4">
<param name="stickersUp" value="5,6,6,5,5,6,6,6,5">
</applet> <applet code="RubikPlayer.class" codebase=3 width="250" height="250">
<param name="scrptLanguage" value="SupersetENG">
<param name="scrpt" value="U'R2URU'R'U">
<param name="stickersFront" value="6,6,5,0,0,6,0,6,6">
<param name="stickersRight" value="4,6,6,6,6,6,6,6,6">
<param name="stickersDown" value="2,6,6,2,2,6,2,6,6">
<param name="stickersBack" value="6,6,3,6,3,3,6,6,3">
<param name="stickersLeft" value="4,4,6,4,4,4,4,4,4">
<param name="stickersUp" value="5,6,6,5,5,6,6,6,0">
</applet> <applet code="RubikPlayer.class" codebase=3 width="250" height="250">
<param name="scrptLanguage" value="SupersetENG">
<param name="scrpt" value="U'R'URU'R'U">
<param name="stickersFront" value="5,6,6,0,0,6,0,6,6">
<param name="stickersRight" value="6,6,6,6,6,6,6,6,6">
<param name="stickersDown" value="2,6,6,2,2,6,2,6,6">
<param name="stickersBack" value="6,6,3,6,3,3,6,6,3">
<param name="stickersLeft" value="4,4,0,4,4,4,4,4,4">
<param name="stickersUp" value="5,6,6,5,5,6,4,6,6">
</applet> <applet code="RubikPlayer.class" codebase=3 width="250" height="250">
<param name="scrptLanguage" value="SupersetENG">
<param name="scrpt" value="U'RUR'U'RU">
<param name="stickersFront" value="4,6,6,0,0,6,0,6,6">
<param name="stickersRight" value="6,6,6,6,6,6,6,6,6">
<param name="stickersDown" value="2,6,6,2,2,6,2,6,6">
<param name="stickersBack" value="6,6,3,6,3,3,6,6,3">
<param name="stickersLeft" value="4,4,5,4,4,4,4,4,4">
<param name="stickersUp" value="5,6,6,5,5,6,0,6,6">
</applet>
<P> 然後說說練習的方法..層先法比較基礎..一次只還原一個塊..觀察比F2L來說也會簡單一點..因為我們只需要找一個塊就行..在還原角塊的時候..我們並不是盯著正在還原的那個角塊..因為通過練習我們己經熟悉了公式..知道肯定可以把它還原..我們要做的是開始尋找下一個要還原的角塊..第一目標先觀察右層有哪些角塊可以還原到第一層..沒有的話再到左層去尋找..</P>
<P> </P>
[ 本帖最后由 录 于 2008-3-15 20:01 编辑 ] |
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