- 最后登录
- 2008-9-11
- 在线时间
- 40 小时
- 阅读权限
- 10
- 注册时间
- 2008-5-29
- 积分
- 79
- 帖子
- 73
- 精华
- 0
- UID
- 33244
- 性别
- 保密
- 积分
- 79
- 帖子
- 73
- 精华
- 0
- UID
- 33244
- 性别
- 保密
|
<P class=MsoNormal style="MARGIN: 0cm 0cm 0pt"><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'"><FONT color=#000000>第一步:上层角块全部还原,过于简单,不介绍。</FONT></SPAN></P>
<P class=MsoNormal style="MARGIN: 0cm 0cm 0pt"><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'"><FONT color=#000000>第二步:下层两角块位置互换</FONT></SPAN></P>
<P class=MsoNormal style="MARGIN: 0cm 0cm 0pt"><FONT color=#000000><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">左下角与右下角互换:(FDF<FONT face="Times New Roman">'</FONT>D<FONT face="Times New Roman">'</FONT></SPAN><SPAN lang=EN-US><FONT face="Times New Roman">)(R'D'R</FONT></SPAN><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">)</SPAN></FONT></P>
<P class=MsoNormal style="MARGIN: 0cm 0cm 0pt"><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'"><FONT color=#000000>解释:就是将右上角块移至右下位置,然后再用另一个方法移回去。此方法最多运用两次就可将下层角块位置复原。</FONT></SPAN></P>
<P class=MsoNormal style="MARGIN: 0cm 0cm 0pt"><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'"><FONT color=#000000>第三步:下层三角块颜色复原</FONT></SPAN></P>
<P class=MsoNormal style="MARGIN: 0cm 0cm 0pt"><FONT color=#000000><SPAN lang=JA style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'; mso-fareast-language: JA">三角块同时原地顺时针旋转</SPAN><SPAN lang=EN-US style="mso-fareast-language: JA"><FONT face="Times New Roman">90</FONT></SPAN><SPAN lang=JA style="FONT-FAMILY: 宋体; mso-fareast-language: JA">゜</SPAN><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">:将不旋转的角块置于右下角位置,(RBLF)(RBLF)(RBLF)</SPAN></FONT></P>
<P class=MsoNormal style="MARGIN: 0cm 0cm 0pt"><FONT color=#000000><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">解释:此方法最多运用两次就可完成全部角块复原工作。不再提示逆时针操作,不怕麻烦就连拧</SPAN><SPAN lang=EN-US><FONT face="Times New Roman">24</FONT></SPAN><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">下。</SPAN></FONT></P>
<P class=MsoNormal style="MARGIN: 0cm 0cm 0pt"><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'"><FONT color=#000000>第四步:边块还原</FONT></SPAN></P>
<P class=MsoNormal style="MARGIN: 0cm 0cm 0pt"><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'"><FONT color=#000000>边块还原一般可以先将魔方的第二层还原,然后是第一层,再复原第三层。</FONT></SPAN></P>
<P class=MsoNormal style="MARGIN: 0cm 0cm 0pt"><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'"><FONT color=#000000>这里只提供一个初级公式,只要不在乎时间还原整个魔方是没有任何问题的。</FONT></SPAN></P>
<P class=MsoNormal style="MARGIN: 0cm 0cm 0pt"><FONT color=#000000><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">如图,欲将前下方的边块移至前上位置,操作步骤:(L<FONT face="Times New Roman">'</FONT>RF</SPAN><SPAN lang=EN-US><FONT face="Times New Roman">2</FONT></SPAN><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">LR<FONT face="Times New Roman">'</FONT>D2)</SPAN><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">,此时后下位置的边块会发生移动。为此一般需要将一块没用的边块移到该位置,这样就会使得未还原的边块越来越少,直至还原整个魔方。</SPAN></FONT></P>
<P class=MsoNormal style="MARGIN: 0cm 0cm 0pt"><FONT color=#000000><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">如果你用了</SPAN><SPAN lang=EN-US><FONT face="Times New Roman">ABC</FONT></SPAN><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">几步将没用的边块移到后下位置,整个操作步骤为</SPAN><SPAN lang=EN-US><FONT face="Times New Roman">ABC(<FONT face=宋体>L<FONT face="Times New Roman">'</FONT>RF<SPAN lang=EN-US><FONT face="Times New Roman">2</FONT></SPAN><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">LR<FONT face="Times New Roman">'</FONT>D2</SPAN></FONT>)</FONT></SPAN><SPAN lang=EN-US><FONT face="Times New Roman">C-B-A-</FONT></SPAN><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">;有时前下边块与后下边块式同时到位的;只剩下三个边块时,通常会有两种方法,正确的方法能够还原整个魔方,错误的方法会剩下两块需要原地翻身(请注意观察一下后下边块的方向)。</SPAN></FONT></P>
<P class=MsoNormal style="MARGIN: 0cm 0cm 0pt"><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'"><FONT color=#000000>两边块原地翻身的办法:两块互换,产生三个不到位的边块,利用上述操作寻找正确的方法。</FONT></SPAN></P>
[ 本帖最后由 清衫小白 于 2008-6-7 13:53 编辑 ] |
|