求助，5阶魔方最后一层

南生四月雪

求助，5J能否一层一层还原？而不象是大部分层先给的只还原前三层，然后两层一起调，我只想要最后一层还原的方法，不知道各位高手知否？我自己研究出来前四层结果，最后一层怎么也不会了，我用三阶的公式只能调整到最后一层四个角和四个中心棱都对，然后剩下的就不会了，我想问问有没有这样的换棱公式？就是只调整除中心棱和四个角以外的其他棱

南生四月雪

我晕，10楼的我要的是层先法。。。

乌木

<P>有意思的是，四阶公式(M1R M1L' U' )4(M1R' M1L U)4 套用到五阶时要做三遍。不知我弄错没有。</P>
<P>&nbsp;</P>
<applet codebase="5" height="300" width="300" code="de.pirzer.rubik.ProfessorPlayerApp.class">
<param name="colortable" value="0xf8f8f8,0x00732f,0xff4400,0xffd200,0x003373,0x8c000f,0x858585">
  <param name="scrptLanguage" value="SupersetENG">
  <param name="scrpt" value=" (M1R M1L' U' )4(M1R' M1L U)4 \n (M1R M1L' U' )4(M1R' M1L U)4 \n(M1R M1L' U' )4(M1R' M1L U)4   ">
  <param name="scriptProgress" value="0">
  <param name="beta" value="29">
  <param name="stickersFront" value="0,5,0,5,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0">
  <param name="stickersBack" value="3,5,3,5,3,3,3,3,3,3,3,3,3,3,3,3,3,3,3,3,3,3,3,3,3">
  <param name="stickersUp" value="5,3,5,3,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,0,5,0,5">
</applet>

<applet code="RevengePlayer.class" codebase=4 width="300" height="300">
<param name="colortable" value="0xf8f8f8,0x00732f,0xff4400,0xffd200,0x003373,0x8c000f,0x858585">
  <param name="scrptLanguage" value="SupersetENG">
  <param name="scrpt" value="(MR ML' U')4 (MR' ML U)4  ">
  <param name="scriptProgress" value="0">
  <param name="beta" value="29">
  <param name="stickersFront" value="0,5,5,0,0,0,0,0,0,0,0,0,0,0,0,0">
  <param name="stickersBack" value="3,5,5,3,3,3,3,3,3,3,3,3,3,3,3,3">
  <param name="stickersUp" value="5,3,3,5,5,5,5,5,5,5,5,5,5,0,0,5">
</applet>

kexin_xiao

给LZ一个网址,自己看看吧http://www.unicube.tw/5x5index.htm

乌木

<P>如果要用7楼那公式，其前后调动改为M1R2 B2 M1L2&nbsp; 和&nbsp; M1L2 B2 M1R2 ，感觉比7楼的调动法舒服点：</P>
<P>&nbsp;</P>
<P>&nbsp;</P>
<applet codebase="5" height="300" width="300" code="de.pirzer.rubik.ProfessorPlayerApp.class">
<param name="colortable" value="0xf8f8f8,0x00732f,0xff4400,0xffd200,0x003373,0x8c000f,0x858585">
  <param name="scrptLanguage" value="SupersetENG">
  <param name="scrpt" value="M1R2 B2 M1L2 ((M1L' U2)4 M1L' U M1F' U' F2 U M1F U' F2 )  M1L2 B2 M1R2 ">
  <param name="scriptProgress" value="0">
  <param name="beta" value="29">
  <param name="stickersFront" value="0,5,0,5,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0">
  <param name="stickersUp" value="5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,0,5,0,5">
</applet>

[ 本帖最后由 乌木 于 2008-7-12 08:45 编辑 ]

乌木

<P>啊呀，7楼馊主意，馊主意。可以直接套用四阶公式M1R2 B2 U2 M1L U2 M1R' U2 M1R U2 F2 M1R F2 M1L' B2 M1R2的，昨天弄错了，现另贴于下。还有个四阶公式TR2 TF2 U2 M1R2 U2 TF2 TR2也可用，一起贴出。楼上的公式也是四阶的，在五阶中可用，但此处用它不够好。</P>
<P>&nbsp;</P>
<P>&nbsp;</P>
<applet codebase="5" height="300" width="300" code="de.pirzer.rubik.ProfessorPlayerApp.class">
<param name="colortable" value="0xf8f8f8,0x00732f,0xff4400,0xffd200,0x003373,0x8c000f,0x858585">
  <param name="scrptLanguage" value="SupersetENG">
  <param name="scrpt" value="M1R2 B2 U2 M1L U2 M1R' U2 M1R U2 F2 M1R F2 M1L' B2 M1R2 ">
  <param name="scriptProgress" value="0">
  <param name="beta" value="29">
  <param name="stickersFront" value="0,5,0,5,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0">
  <param name="stickersUp" value="5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,0,5,0,5">
</applet>
<P>&nbsp;</P>
<applet codebase="5" height="300" width="300" code="de.pirzer.rubik.ProfessorPlayerApp.class">
<param name="colortable" value="0xf8f8f8,0x00732f,0xff4400,0xffd200,0x003373,0x8c000f,0x858585">
  <param name="scrptLanguage" value="SupersetENG">
  <param name="scrpt" value="TR2 TF2 U2 M1R2 U2 TF2 TR2 ">
  <param name="scriptProgress" value="0">
  <param name="beta" value="29">
  <param name="stickersFront" value="0,3,0,3,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0">
  <param name="stickersBack" value="3,0,3,0,3,3,3,3,3,3,3,3,3,3,3,3,3,3,3,3,3,3,3,3,3">
</applet>

乌木

<P>这样勉强可以。两棱互换公式为((M1L' U2 )4M1L' U M1F' U' F2 U M1F U' F2 )，之前的M1R2 D U CU' CR'、之后的CR CU U' D' M1R2是临时调动和调回。</P>
<P>&nbsp;</P>
<P>&nbsp;</P>
<applet codebase="5" height="300" width="300" code="de.pirzer.rubik.ProfessorPlayerApp.class">
<param name="colortable" value="0xf8f8f8,0x00732f,0xff4400,0xffd200,0x003373,0x8c000f,0x858585">
  <param name="scrptLanguage" value="SupersetENG">
  <param name="scrpt" value="M1R2 D U CU' CR' ((M1L' U2 )4M1L' U M1F' U' F2 U M1F U' F2 )  CR CU U' D' M1R2 ">
  <param name="scriptProgress" value="0">
  <param name="beta" value="29">
  <param name="stickersFront" value="0,5,0,5,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0">
  <param name="stickersUp" value="5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,0,5,0,5">
</applet>

hopeman

仔细研究一下K4吧，最后一层棱的还原应该能摸索出来。

yzl-34

只会降阶解法，帮不了你

bbshanwei

除了降阶法应该还有其他的方法吧，我没有高阶的魔方所以也不是很了解。等待着一起学习。